int 1x {6 (logx) ^2+ 7logx + 2 } d x =

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Click here:point_up_2:to get an answer to your question :writing_hand:6 the value of int frac e 5 log x

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

∫ dx / (x [6(logx)^2+7logx+2] ) - o1fxhx99

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

int (dx)/(x[(log x)^(2)- 6 log x+5])`

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

Evaluate: `int(e^x(1+xlogx))/xdx`

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

Srinivas – Page 78 – AP Board Solutions

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

Example 38 - Evaluate [log (log x) + 1 / (log x)2 ] dx - Examples

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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